$\left(d^3+3d^2-4d-12\right)y=0$
$16+625r^2\:+\:300r\:+ar\:+180$
$\sqrt{2x\cdot\sqrt{8x^3}}$
$d^{4x}\frac{dy}{dx}=2y^3$
$6b+5a-2b-5b$
$16x-4=y$
$cos^22x\frac{df}{dx}-4f^2=0$
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