$x-8=6$
$\int\frac{1}{x^2\cdot\sqrt{9-x^2}}dx$
$\left(x^5+3\right)^2$
$\frac{\sqrt{9-\left(x+h\right)}-\sqrt{9-x}}{h}$
$x^2\:+6x+9=0$
$\lim_{x\to16}\left(\frac{\sqrt{x+2}-2}{x-2}\right)$
$a^2-2^a-3\:entre\:a+1$
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