$4a^2-20a+24$
$\left|-3\right|+7$
$\frac{dy}{dx}\left(x^4+1\right)^5\left(x-1\right)^2x^4$
$\left(2y+7z\right)\left(4y^2-14yz+49z^2\right)$
$\frac{5}{4}=\frac{x}{4}$
$\frac{x^2-6}{x}$
$10x^2+x-21=0$
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