$h\left(z\right)=\left(z-\sqrt{z}\right)\left(3+8\sqrt[3]{z^2}\right)$

$\frac{1}{4}ka-\frac{1}{8}ka$

$\frac{dy}{dx}=y\left(1-2x\right)$

$x\:\frac{dy}{dx}+4y\:=\:x^3\:-\:x$

$\left(8z-e\right)\left(-9f-3e\right)$

$b3\:-\:125$

$\frac{\left(10+x^6\right)dy}{dx}=\frac{x^5}{y}$