$9x-1<2$
$-6^5$
$\lim_{x\to\infty}\left(\frac{1-sin\left(x\right)}{1+cos\left(2x\right)}\right)$
$x^2+4x=285$
$12m^3n+72mn^4$
$27x^3-8y^{12}$
$\frac{4v^2-4v}{1+v}$
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