$n\left(n+1\right)$
$\left(2x-3\right)^2=\left(x+5\right)^2-x-6$
$\:\sqrt{\frac{x^2+4x+4}{x^2-4}}$
$6a^2-12a+6$
$\left(-3x+6y-8\right)-\left(4x-5y\right)$
$6x^2+3xy$
$a^2b-3ab^2+2a^2b+5ab^2+ab^2$
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