$\int\left(\sec^2\left(\frac{1}{3}x\right)\right)dx$
$20^3\cdot20^{-3}$
$\sec^2+\left(a\right)=1+\tan^2\left(a\right)$
$\frac{d}{dx}y=tan\left[cos\left(3x\right)\right]$
$\left(5x^2y^2+3\right)\left(5x^2y^2-7\right)$
$\left(x-2a\right)^2$
$\lim_{x\to0\:}\left(x^2-1\right)$
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