$y\left(y'\right)^2+2xy'-y=0$

$\left(x-5\right)\left(z-3\right)$

$\frac{\sin\left(x\right)\cos\left(x\right)}{\tan\left(x\right)}=1-\sin\left(x\right)$

$2x^2-8x+7$

$\lim_{x\to\infty}\left(ln\left(8x^3-5\right)-ln\left(2x^3+6\right)\right)$

$\left(4x^2+3x+2\right)\left(x-5\right)$

$6\sin^2\left(x\right)=-13\sin\left(x\right)-7$