$\sin^3\left(z\right)\cos^2\left(z\right)=\sin^3\left(z\right)-\sin^5\left(z\right)$
$\int\sqrt{5}\left(3-5x\right)dx$
$\left(6x^2+x^3\right)$
$x^2-2x+2^2$
$2x^4y-4x^2y^2+2x^2y$
$3m\:-10\:\:50$
$\frac{d}{dx}x\sqrt{16-x^2}$
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