$\:\frac{tan^2\theta\:}{sec^2\theta\:\:}$
$7-3x\le-2$
$-x^2+3x-7\ge0$
$8x+4y-3x+4-3y$
$8\:-\:\left(-8\right)\:+\:\left(-3\right)$
$\left(x-2\right)^2-3\left(x+6\right)=4$
$\frac{d^2y}{dt^2}=-w^2x\left(t\right)$
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