$\frac{du}{dt}=3x-2t$
$\sqrt[4]{n^3}$
$\int\frac{-2}{\left(x-1\right)^3}dx$
$9a-3b+5-a-b+4-5a+4b-8$
$21c-8c$
$\left[\left(-9\right)-\left(-5\right)+\left(-12\right)\right]-\left[-9-11\right]$
$\frac{1}{3}\left(x+5\right)=\frac{7}{3}$
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