$\left(2x^2+x^5\right)^3$
$f\left(x\right)=\left(\frac{2}{x-1}\right)^5$
$\left(2a\:-\:b\:-\:c\right)\:\left(2a\:-\:b\:+\right)$
$\:-\:2h\:-\:\left(-\:8h\right)$
$12\left(\sin\left(a\right)cos\left(a\right)\right)=6sin2a$
$\frac{x^4y^4-64a^6}{x^2y^2+8a^3}$
$\sqrt{\left(358.85m\right)^2}+\left(-12.5m\right)^2$
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