$-4y^2\left(-7y\right)$

$-\frac{1}{3}\ln\left(y^3-1\right)=\ln\left(x\right)$

$\frac{3x^3+x^2+2}{\left(x^2+1\right)^2}$

$\frac{26x^4-6}{x\:+8}$

$5+-7+-4-11$

$\lim_{x\to0}\left(\frac{\sin^2\left(x\right)\cdot\tan^4\left(x\right)}{\left(x^2+1\right)^2}\right)$

$\sin\left(2x\right)+\cos\left(2x\right)\cot2x=\csc2x$