$-40\cdot2-5$
$\frac{dx}{dy}=x+3$
$\lim_{x\to0}\left(\frac{x^2-25}{\ln\left(x\right)-\ln\left(5\right)}\right)$
$16a^4+8a^3+a^2$
$2x^2-5x+7=\:0$
$49z^2-64$
$\left(x\left(\frac{1}{2}\right)+x\left(\frac{1}{4}\right)-1\right)\left(3\right)$
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