$\left(3+y\right)^7$
$\sqrt[3]{27x^3}$
$\tan\left(90\right)=\cot\left(x+10\right)$
$-x-5x-8x+8x$
$\frac{\sqrt{1+\tan^2\left(x\right)}}{\tan\left(x\right)}$
$10\left(5\right)^2$
$\frac{dy}{dx}=\frac{y}{x+xe^{\frac{y}{e}}}$
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