$\frac{tan^2xcosx}{\left(1-cosx\right)\left(1+cosx\right)}$
$\frac{x+4}{8}=2$
$\frac{\:2x^4-5x^3+7x^2-3x+1}{x+1}$
$\int\sqrt[3]{x^3+1}3x^2dx$
$2b^3c^6+16b^2c^6$
$-3+4+2+1$
$8x^3+2x^4+x^2$
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