$1+\cot\left(x\right)\tan\left(b\right)$
$\frac{dy}{dx}=\frac{-1}{\left(400+x\right)}$
$\frac{x^3-2}{x+3}$
$\left(6\:\right)-\:\left(-14\right)\:_{\:\left(-9\right)}$
$5x^4y+4z\left(5x^4y-4z\right)$
$-x-3=5x+123$
$\left(2a^2-3b\right)\left(4a^4+6a^2b^2+4b^4\right)$
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