$\left(\frac{1}{7}y^{2t+1}-\frac{1}{4}y^{t+2}\right)^2$
$\left(4x^3y-2z^5\right)^2$
$\left(3t\:+7\right)\:\left(3t\:+\:2\right)\:$
$x^2+2x-\frac{8}{x^2}+9x+20$
$52\left(-46\right)$
$6x-4\ge4x+8$
$\int\frac{x^2+2x+1}{x\left(2x+1\right)\left(x+2\right)}dx$
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