$\frac{x}{\frac{1}{3}}$
$tan\left(cos^{-1}\left(3x\right)\right)$
$\left(x+4\right)20\cdot\left(x+4\right)^2$
$\log\:_{10}\left(6x-1\right)-\log\:_{10}\left(x+4\right)=0$
$6\left(-4+15\right)$
$\frac{dx}{dt}=\left(2t+10\right)x^{10}$
$39^2$
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