$-3a^2b^3\left[7b^2-6b+19\right]$
$\left(x+3\right)\left(x-1\right)\left(x-5\right)$
$-7x^2+12x+36$
$\frac{dy}{dx}=\frac{2x^3}{\left(y^2\right)}$
$tan\left(x\right)sin\left(x\right)=2sin^2\left(x\right)$
$\left(1\:+\:cos\left(x\:+\:y\right)\right)\:+\:cos\left(x\:+\:y\right)\frac{dy}{dx}=\:0$
$5-\left[-3-\left(4-7\left(3\right)-9\right)\right]+6$
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