$x^2+7x=0$
$3^2+3+3\left(2\right)$
$2ac-2ad+3bc-3bd$
$\frac{2x^3-3x^2+4x-5}{x-2}$
$2x+3<3x-10$
$-6+\left(-4\right)-\left(-5\right)+\left(-2\right)$
$\frac{x^6-64}{x^3-8}$
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