$\left(8x^3+54\right)^2$
$\left(-3a\right)\left(-4a^2\right)$
$-\:2\:-\:1\:+\:3a\:-\:3$
$1+x>0$
$3^2-\left(4-3\cdot2\right)+6+2\cdot\left(24:4\right)$
$12+9x-6x-19$
$4\left(12\right)+4\left(8\right)$
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