$\frac{tan\:x-sec\:x}{sen\:x}$
$16x+9=9y-2x$
$4x^2+3x$
$\sec\left(4x+9\right)-\csc\left(3w+4\right)=0$
$\frac{12}{3}-2$
$\int\left(x\left(1-x\right)^2\right)dx$
$\:14x^2y^2-28x^3+56x\left\{4\right\}$
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