$-3\cdot14$
$16:-5$
$x+11=-23$
$\left(6m-4m+10a-5\right)+\left(10m-4m+5a-9\right)$
$\left(x^4-\frac{1}{2}x^3\right)^2$
$3+sec^2x$
$\left(9x+4\right)\left(16x+64\right)$
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