$2\cos^2\left(x\right)+\sin^2\left(x\right)=2$
$2x-5<-3$
$\tan x\cos^2x=2\tan x$
$2.5198420997897464\cdot3$
$x^2-2x-7=8$
$\left(5x^2-4x+6\right)\left(-2x+3\right)$
$\frac{\left(\sec\left(x^3+x^2\right)\right)^4}{\cos\left(x\right)}$
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