$\frac{cos^2x\cdot sen^2x+cos^4x}{sen^2x}$
$3y'\:+xy\:=\:x$
$\frac{-6x^3+2x^2+9x+3}{-2x^2+5}$
$7w-w$
$\frac{4}{9}y=\frac{8}{3}$
$\frac{x^2-25}{x^2-9x+20}$
$4x^2-4x+33=0$
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