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Exercise

$\frac{d}{dx}\left(\tan\left(x+y\right)=ln\left(x\right)+5y\right)$

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Final answer to the exercise

$y^{\prime}=\frac{-x\sec\left(x+y\right)^2+1}{x\left(\sec\left(x+y\right)^2-5\right)}$

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  • Integrate by partial fractions
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