$\frac{9a^2-3a+6}{3a}$
$\frac{1}{1^2}$
$\left(4x+5\right)\left(16x^{2\:}+20x+25\right)$
$4x+y+3x$
$y^2\left(8-x\right)=16x^3$
$\sqrt{6x^2-3x^2y^3}$
$\frac{dy}{dx}=y^3-2y$
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