$\int\frac{3x^2+2x+4}{\left(x+1\right)\left(x^2+16\right)}dx$
$\cos\left(250\right)=\frac{800}{x}$
$4m^2-44m+121$
$\frac{x+3}{3}+\frac{x+2}{4}<5$
$\frac{dy}{dx}=0,5x+y$
$\left(x^3-8\right)+\left(3x^2+7\right)$
$f\left(x\right)=x^2+3x$
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