$\int\frac{4}{\left(x-4\right)\left(x^2+2x+6\right)}dx$

$y=y$

$\int\left(\frac{-2\sqrt{x}}{3}\right)dx$

$\int\frac{\left(6-lnx\right)^2}{x}dx$

$\left(\frac{2x}{3y}+\frac{3y}{2x}\right)^2$

$\int_1^{\infty}\left(\frac{\ln\left(x\right)}{\left(10x\right)}\right)dx$

$25x^2+40xy+16y^2-9$