$\frac{x\left(x-1\right)}{x}$
$\frac{-90+40x^2}{2x-3}$
$\lim_{h\to0}\left(\frac{\left(4+h\right)^2-16}{h}\right)$
$\sin\left(8-9x\right)$
$6,5-4,91$
$2x-6y+7x+2y$
$\frac{x^4+4x^3-4x^2-5}{-2}$
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