$x^3-3x^2+6x$
$y=e^{3x}\cdot ln\sqrt{x}$
$-2\left(-2x+4\right)+4x$
$5y^4\cdot4yx^3$
$\lim_{h\to0}\left(\frac{\sqrt[3]{5+h}-\sqrt[3]{5}}{h}\right)$
$\left(x^3+3\right)\left(n^3-6\right)$
$36^2-12xy+y^2$
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