Final Answer
$\frac{-16\cdot 2^{'1}x}{\left(x^2+4\right)^2}$
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Step-by-step Solution
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Simplifying
$\frac{d}{dx}\left(\frac{8\cdot 2^{'1}}{x^2+4}\right)$
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$\frac{d}{dx}\left(\frac{8\cdot 2^{'1}}{x^2+4}\right)$
Learn how to solve differential calculus problems step by step online. Find the derivative of d/dx(8/(x^2+4)2^'1). Simplifying. Apply the quotient rule for differentiation, which states that if f(x) and g(x) are functions and h(x) is the function defined by {\displaystyle h(x) = \frac{f(x)}{g(x)}}, where {g(x) \neq 0}, then {\displaystyle h'(x) = \frac{f'(x) \cdot g(x) - g'(x) \cdot f(x)}{g(x)^2}}. The derivative of the constant function (8\cdot 2^{'1}) is equal to zero. Any expression multiplied by 0 is equal to 0.
Final Answer
$\frac{-16\cdot 2^{'1}x}{\left(x^2+4\right)^2}$