$\sin\left(2x\right)+\sin\left(x\right)=6\cos\left(x\right)+3$
$13-7+2-3-1$
$x^2-12x=-27$
$x^{\frac{1}{2}}\cdot x^{\frac{4}{6}}$
$x+12\left(x-1\right)>0$
$\frac{3}{2}\cos\left(13x\right)=\frac{1}{2}$
$27-\left(-10\right)$
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