$m^3-y^3$
$-10.24+98$
$40\cdot\frac{10}{\left(-20\right)}$
$\lim_{x\to0}\left(\frac{tan2x-sin2x}{0.5x^3}\right)$
$cscx\left(sinx-1\right)\:=\:1-cscx$
$a+2=10$
$\lim_{x\to0}\left(\frac{1-\cos\left(x\right)}{x\left(\sqrt{x+1}-1\right)}\right)$
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