$7>\sqrt{40}$
$\left(1+x\right)\frac{d}{dx}\left(y\right)=y$
$\left(z^2+2\right)\left(z^2-3\right)$
$y'\:=\:3y\:+\:4$
$6\:\cdot\:-9\:+\:5\:-18$
$\frac{d}{dx}y^2-y-x^2$
$\left(3x-9\right)\left(3x+4\right)$
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