$\frac{3+x}{3-x}\ge\:\:1$
$\frac{\left(-9\right)+\left(-3\right)}{6}$
$-6-\left(-27\right)+12$
$2r^2.\:r$
$\sqrt{-252}$
$\frac{19c^7}{38c^7}=\frac{c}{2}$
$\int\left(x^3\cdot\cos\left(\frac{x}{2}\right)+\frac{1}{2}\right)\cdot\sqrt{4-x^2}dx$
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