$\left(\frac{1}{2}x^3+\frac{7}{6}y^2\right)\left(\frac{1}{2}x^3+\frac{7}{6}y^2\right)$
$\lim_{x\to3}\left(\frac{x^3}{senx-x}\right)$
$\frac{x^3-1}{x^5-6x^4+12x^3-8x^2}$
$5-3x=-4$
$-8\left(-7+3-1\right)$
$\sqrt{27.3}$
$3x^3-2x^2+5x-3y\:4x^2-3x+2$
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