$\int\frac{4z}{\left(z-1\right)^2\left(z+1\right)}dz$
$-4.9x^2+17.667x$
$cos\left(\frac{x}{2}\right)=0.16$
$x^{2}-4x>221$
$5x-2-4x+8$
$2\cos\left(2\right)x-\sin\left(2\right)x+2\cos\left(x\right)=0$
$x^2-14x+63=0$
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