$y'+\frac{1}{3}y=e^xy^4\:$
$u'=4y+2u$
$\left(7x^3+y+4\right)^2$
$8c-20c-c$
$\left(-x^4\:+\:3x^2-\:2x\:+\:1\right):\left(x\:+\:1\right)\:$
$2 x ^ { 3 } + 3 x ^ { 2 } - 1$
$\left(\frac{b^{\frac{1}{2}}}{b^{\frac{1}{4}}}\right)^{\frac{1}{3}}$
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