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# Find the derivative of $\arcsin\left(2x-3\right)$

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##  Final answer to the problem

$\frac{2}{\sqrt{1-\left(2x-3\right)^2}}$
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##  Step-by-step Solution 

How should I solve this problem?

• Choose an option
• Find the derivative using the definition
• Find the derivative using the product rule
• Find the derivative using the quotient rule
• Find the derivative using logarithmic differentiation
• Find the derivative
• Integrate by partial fractions
• Product of Binomials with Common Term
• FOIL Method
• Integrate by substitution
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1

Taking the derivative of arcsine

$\frac{1}{\sqrt{1-\left(2x-3\right)^2}}\frac{d}{dx}\left(2x-3\right)$

Learn how to solve differential calculus problems step by step online.

$\frac{1}{\sqrt{1-\left(2x-3\right)^2}}\frac{d}{dx}\left(2x-3\right)$

Learn how to solve differential calculus problems step by step online. Find the derivative of arcsin(2x-3). Taking the derivative of arcsine. The derivative of a sum of two or more functions is the sum of the derivatives of each function. The derivative of the constant function (-3) is equal to zero. The derivative of the linear function times a constant, is equal to the constant.

##  Final answer to the problem

$\frac{2}{\sqrt{1-\left(2x-3\right)^2}}$

##  Explore different ways to solve this problem

Solving a math problem using different methods is important because it enhances understanding, encourages critical thinking, allows for multiple solutions, and develops problem-solving strategies. Read more

SnapXam A2

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1
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3
4
5
6
7
8
9
0
a
b
c
d
f
g
m
n
u
v
w
x
y
z
.
(◻)
+
-
×
◻/◻
/
÷
2

e
π
ln
log
log
lim
d/dx
Dx
|◻|
θ
=
>
<
>=
<=
sin
cos
tan
cot
sec
csc

asin
acos
atan
acot
asec
acsc

sinh
cosh
tanh
coth
sech
csch

asinh
acosh
atanh
acoth
asech
acsch

###  Main Topic: Differential Calculus

The derivative of a function of a real variable measures the sensitivity to change of a quantity (a function value or dependent variable) which is determined by another quantity (the independent variable). Derivatives are a fundamental tool of calculus.