$40x^9+48x^5+8x$

$\frac{\left(2x^4-3x^3+8x^2-6x+5\right)}{\left(2x-x+5\right)}$

$\lim_{x\to2}\left(\frac{\left(3-\sqrt{2x+5}\right)}{x^2-4x+4}\right)$

$\frac{dy}{dx}=\sin\left(2x\right)=y\cos\left(2x\right)$

$6\sqrt{2}\cdot6\sqrt{2}$

$\left(\frac{-3}{4}\right)x\frac{2}{5}$

$9x^2+3$