$\int\left(\frac{x+4}{25x^2+80x+80}\right)dx$
$x^2-5x-4\ge0$
$4x+6x$
$\sin\left(\tan^{-1}\frac{x}{6}\right)$
$8m-6n-4n-12m+8$
$\int_{\tan\left(x\right)}^{\sec\left(x\right)}\left(2x\cos\left(y\right)\right)dx$
$5x-6=3x-8$
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