$\sqrt{10^2-3^2}$
$\sqrt[5]{2^5}+\sqrt[5]{3^5}$
$\lim_{x\to\infty}\left(\frac{2x+3}{x^2+1}\right)$
$\int\frac{2x^3-3x^2+2}{x+1}dx$
$\frac{x+25}{7-x}\ge3$
$2xy+x-1=0$
$\lim_{x\to0}\left(x-\frac{\pi}{2}\right)\cdot\tan\left(x\right)$
Get a preview of step-by-step solutions.
Earn solution credits, which you can redeem for complete step-by-step solutions.
Save your favorite problems.
Become premium to access unlimited solutions, download solutions, discounts and more!