$\int_0^{16}\left(\frac{4}{\sqrt[3]{x-8}}\right)dx$

$x^2y-4x^3+16=0$

$82-\left(-34\right)$

$y-817=13$

$\lim_{x\to0}\left(\frac{\sin\left(x\right)-\sin\left(2x\right)}{x-\sin\left(x\right)}\right)$

$\lim_{x\to\infty}\left(\frac{x}{x^2-2x}\right)$

$\int\left(\frac{x^3}{\sqrt[3]{x^4-1}}\right)dx$