$x^2-12x+40$
$\frac{3x+3}{x^2-1}$
$\lim_{x\to1}\left(\frac{e^x}{1-x}\:-\frac{x}{ln\:x}\right)$
$\frac{64^6-125}{4^2-5}$
$5mx+2=3m+x$
$18\cdot\left(-31\right)+50$
$\left(2a\:-\:2b\right)^2$
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