$x+7=-x+1$
$\int x ^ { 2 } ( x ^ { 3 } - 4 ) ^ { 2 } d x$
$\frac{d}{dx}\left(\frac{1}{1+4x}\right)$
$2.5\:\cdot\:-3\frac{4}{5}$
$\int\frac{x^2+1}{9-x^2}dx$
$3x^2-6x+4=0$
$\pi\int_{\frac{1}{2}}^1\left(\frac{1}{x}\right)dx$
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