$16x^8y^4-\frac{1}{9}x^6z^2$
$\left(14a^7b^6\right)+\left(10b^{11}\right)$
$\int x-4dx$
$\frac{dy}{dx}=-e^{2\left(x+y\right)}$
$\lim_{x\to\infty}\left(6x\right)^{\frac{1}{11x}}$
$6\:4\:x\:4\:4\:-2\:5\:y\:2\:$
$\left(x+2\right)\left(2x^3-2x^2+3x-1\right)+-4$
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