$\frac{27}{9}$
$2>x+\frac{4}{3}$
$6x^3+7x^2-9x+2$
$3.\:\left[2+\:\left(8-9\right)\right]$
$\left(-3x^3+2x^2-5x+9\right)+\left(-x^3+2x^2-5x-6\right)$
$\:27x^3-216$
$\frac{\tan\left(x\right)+\sin\left(x\right)}{1+\cos\left(x\right)}$
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