$\left(-y+4\right)^3$
$\sec\left(x\right)^2+\csc\left(x\right)^2=\sin^2\left(x\right).\sec^2\left(x\right)$
$0,\overline{15}+0,15:0,15$
$-1\:restar\:-9$
$\frac{3x^3+8x^2-2}{3x+x^2-1}$
$\sqrt{60a^2b^7}$
$45x^2-9x+9$
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