$-0+2\cdot4$
$\int\frac{e^{6y}+8}{e^{2y}}dy$
$8\sqrt{x^4}y^2z^3$
$y'-\left(x-y+1\right)^2=x-y$
$\int\left(\frac{1}{4x^4}\right)dx$
$\frac{d}{dx}\:6x^3y-2x^2=40$
$9b^8\:+\:24b^3$
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